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The distance between (2, 0) and (5, -1) is: 9. 0. 10. \sqrt10
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Jan 12, 2018
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The distance between (2, 0) and (5, -1) is:
9.
0.
10.
Mathematics
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Hakoja
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distance = square root ((x2 - x1)^2 + (y2 - y1)^2)
(2,0)...x1 = 2 and y1 = 0
(5,-1)..x2 = 5 and y2 = -1
sub and solve
d = sqrt ((5 - 2)^2 + (-1 - 0)^2)
d = sqrt ((3^2) + (-1^2))
d = sqrt (9 + 1)
d = sqrt 10 <==
Jack Kinsey
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Jan 18, 2018
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Jack Kinsey
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