Question

A given line has the equation 2x + 12y = −1.

What is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (0, 9)?

Answer 1

the answer is d

Explanation:

Answer 2

2x + 12y = -1
12y = -2x - 1
y = - 1/6x - 1/12...slope here is -1/6. A perpendicular line will have a negative reciprocal slope. All that means is flip the slope and change the sign. So our perpendicular line will need a slope of 6.

y = mx + b
slope(m) = 6
(0,9)...x = 0 and y = 9
sub and find b, the y int
9 = 6(0) + b
9 = b

so ur perpendicular equation is : y = 6x + 9 <==