Question

Write the sum using summation notation, assuming the suggested pattern continues. -8 - 3 + 2 + 7 + ... + 67

Answer 1

`a_1=-8\\ r=5\\ a_n=67\\\\ a_n=a_1+(n-1)r\\ 67=-8+(n-1)\cdot5\\ 67=-8+5n-5\\ 5n=80\\ n=16\\\\ \displaystyle \sum_(i=1)^(16)(-8+(n-1)\cdot5)=\sum_(i=1)^(16)(-8+5n-5)=\boxed{\sum_(i=1)^(16)(5n-13)}`