Question

A can of hairspray has a volume of 684 mL and contains 6.43 g of carbon dioxide as the propellant what is the pressure inside the can at 25°C

Answer 1

Use ideal gas equation

pV = n RT => p = nRT / V

T = 25 + 273.15 K = 298.15 K

V = 684 ml = 0.684 l

R = 0.0821 atm * l / (K*mol)

n = mass / molar mass =

molar mass of CO2 = 12 g/mol + 2*16 g/mol = 44 g/mol

n = 6.43 g / 44 g/mol = 0.14614 mol

=> p = 0.14614 mol * 0.0821 atm*l /(K*mol) * 298.15K / 0.684 l = 5.23 atm

Answer: p = 5.23 atm