Question

Find three consecutive integers such that the sum of the first and twice the third is one more than three times the second.

Answer 1

So we have A, B and C
B= A+1
C= A + 2
A + 2C = 3B + 1
Now substitute for A

A + 2(A+2) = 3(A+1) +1 now distribute A + 2A + 4= 3A + 3 + 1 now simplify

3A + 4 = 3A + 4 since the values are equal you need to only find any three consecutive integers