Question

What is the distance between the points (3,7) and (15,16) on a coordinate plane?

Answer 1

Use the distance formula:
`distance = √((x_2 - x_1)^2 + (y_2 - y_1)^2)`


`√((15 - 3)^2 + (16 - 7)^2) \\ \\ √(12^2 + 9^2) \\ \\ √(144 + 81) \\ \\ √(225) \\ \\ 15`

So, 15 units is the answer.

Answer 2

distance = Sqrt((x2-x1)^2 +(y2-y1)^2)

15-3 =12

16-7=9

12^2 = 144

9^2 = 81

144+81 = 225

square root of 225 = 15

the distance is 15