Question

The base of the parallelogram, b, can be found by dividing the area by the height. If the area of the parallelogram is represented by 6x2 + x + 3 and the height is 3x, which represents b, the length of the base

Answer 1

In this item, we have:

A = 6x² + x +3
h = 3x

where ''A'' is area and ''h'' is height. From the statement above,
length of base, b = A / h

b = (6x² + x + 3)/3x

Thus, the expression for the length of the base is 6x²+x+3 / 3x.

Answer 2

`2x+(1)/(3)+(1)/(x)=Base`

Explanation:

Given: The area of the parallelogram is
`6x^2+x+3` and the height is 3x.

To find: The base of the given parallelogram.

Solution: It is given that The area of the parallelogram is
`6x^2+x+3` and the height is 3x.

Now, area of parallelogram is given as:

`A=b{*}h` where b is the base and h is the height of teh gievn parallelogram.

Substituting the given values, we have

`6x^2+x+3=b{*}3x`

⇒
`(6x^2+x+3)/(3x)=Base`

⇒
`(6x^2)/(3x)+(x)/(3x)+(3)/(3x)=Base`

⇒
`2x+(1)/(3)+(1)/(x)=Base`

which is the required expression for the base of the given parallelogram.