Those are all lines...
So the x interval is from -2 to 3, because of x=-2 and x=3
The upper line is y(u)=4x and the lower line is y(l)=x-5
So the area between the two lines is:
A=⌠y(u)-y(l) dx
A=⌠4x-x+5 dx
A=⌠3x+5 dx
A=[3x^2/2+5x]
A=[(3x^2+10x)/2], x=[-2,3]
A=(1/2)(27+30-(12-20))
A=(1/2)(57+8)
A=(1/2)(65)
A=32.5 u^2