Answer:
30.942 g of NaCl
Step-by-step explanation:
The balance chemical equation is
CuCl₂ + 2 NaNO₃ → Cu(NO₃)₂ + 2 NaCl
Calculate moles of CuCl₂
Moles = 37 g / 134.45 g/mol = 0.275 mol
Calculate moles of NaNO₃
Moles = 45 g / 84.99 g/mol = 0.529 mol
According to balanced chemical equation the mole ratio of CuCl₂ : NaNO₃ is 1 : 2.
Hence,
0.275 : 0.550 or 0.529 : 0.264
This means that the NaNO₃ is the limiting reagent.
Now mole ratio of NaNO₃ and NaCl is 2 : 2 or 1 : 1.
Hence, 0.529 mol of NaNO₃ will produce 0.529 mol of NaCl.
Now,
Mass = Moles x M.Mass
Mass = 0.529 mol x 58.44 g/mol
Mass = 30.942 g of NaCl