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4 votes
Which is the focus of a parabola with equation y^2=-12x?

A. (-3,0)
B. (0, -3)
C. (0,3)
D. (3,0)

2 Answers

3 votes
p is 3 .and its horizontal parabola it's focus is (a-p,b) so (-3,0)
User Helpful
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8.2k points
3 votes

Answer:

Focus of the given parabola is (-3,0)

Explanation:

Given equation of parabola is:

y² = -12x

Standard equation of parabola is :

y² = 4px

Parabola opens right or left.

Focus of this parabola is (p,0)

y² = -12x is opens left.

y² = 4(-3)x

Here value of p = -3

So, the focus of given parabola is : (-3,0)

That's the final answer.

I hope its help you.

User Priyank Bolia
by
7.6k points

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