Find the points on the curve y = 2x3 + 3x2 − 12x + 1 where the tangent line is horizontal.

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asked Apr 9, 2018 67.1k views

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Kawtousse · Answer 1 · 2018-04-14T09:07:23+0000

y = 2x³ + 3x² -12x + 1
its tangente is horizontal (tan =0), if it's derivative = 0
y' = 6x² + 6x -12 = 0
Solving this quadratic equation gives :
x= =1 & x = -2
At (1,0) & at (-2,0) tangent is horizontal

Find the points on the curve y = 2x3 + 3x2 − 12x + 1 where the tangent line is horizontal.

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