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Find the points on the curve y = 2x3 + 3x2 − 12x + 1 where the tangent line is horizontal.
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Find the points on the curve y = 2x3 + 3x2 − 12x + 1 where the tangent line is horizontal.

User Shenedu
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1 Answer

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y = 2x³ + 3x² -12x + 1
its tangente is horizontal (tan =0), if it's derivative = 0
y' = 6x² + 6x -12 = 0
Solving this quadratic equation gives :
x= =1 & x = -2
At (1,0) & at (-2,0) tangent is horizontal
User Kawtousse
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8.1k points
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