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There are 42 boys and girls participating in an essay-writing competition. Of the competitors, 21 are in seventh grade, 14 are in eighth grade, and 7 are in ninth grade. What is the probability of an eighth grader winning the competition? Which simulation(s) can be used to represent this situation?

User Colm Doyle
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2 Answers

5 votes
P(8th grader winning) = 14/42...reduces to 1/3

simulate this by using a number generator with numbers 1 - 6.....with 1 - 3 representing 7th graders, 4 and 5 representing 8th graders, and 6 representing 9th graders
User Pablo Jadzinsky
by
8.2k points
1 vote

Answer: Our required probability is 0.34.

Explanation:

Since we have given that

Number of seventh grade student s= 21

Number of eight grade students = 14

Number of ninth grade students = 7

Total number of boys and girls = 42

Probability of an eigthth grader winning the competition would be


(14)/(42)\\\\=\dfra{1}{3}\\\\=0.3333333..................\\\\\approx 0.34

Hence, our required probability is 0.34.

User Jingles
by
7.6k points
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