Question

The sum of 4 consecutive integers is 130. what is the third number in the sequence?

Answer 1

The answer is 33.

Explanation:

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Answer 2

The third number in the sequence 31, 32, 33, 34 is 33

Explanation:

let first number be the smallest number be x.

Consecutive numbers are those numbers that follow each other in order and they should have a difference of 1 between every two numbers.

Then, the four consecutive integers are x , (x+1), (x+2) , (x+3)

Given: the sum of 4 consecutive integers is 130.

From the given condition we have,

`x+(x+1)+(x+2)+(x+3)=130`

Like terms states that contain the same variables raised to the same power.

Combine like terms we get,

`4x+6=130`

Subtract 6 from both the sides, we get

`4x+6-6=130-6`

Simplify we get,

`4x=124`

Divide both sides by 4;
`(4x)/(4)= (124)/(4)`

On simplify we get, the value of x i.e,
`x=31`

the sequence we have, 31, 32, 33, 34,

therefore, the third number in the sequence is, 33.