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What is the equation of the axis of symmetry of the graph of y=ax^2+bx+c

User Ekaterina
by
9.0k points

2 Answers

3 votes

Answer: x=-b/2a

Explanation:

edge.

User Yeeen
by
8.4k points
2 votes

Answer:


x=-(b)/(2a)

Explanation:

we know that

The quadratic equation
y=ax^(2)+bx+c is a vertical parabola

The axis of symmetry in a vertical parabola is a vertical line

The equation of the axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex

The x-coordinate of the vertex is equal to the formula


x=-(b)/(2a)

therefore

the equation of the axis of symmetry is equal to
x=-(b)/(2a)

User Shadowfool
by
7.9k points

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