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How many moles of NaOH are present in 13.0 mL of 0.220 M NaOH?
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How many moles of NaOH are present in 13.0 mL of 0.220 M NaOH?
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Sep 12, 2018
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How many moles of NaOH are present in 13.0 mL of 0.220 M NaOH?
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v=13.0 mL=0.0130 L
c=0.220 mol/L
n=vc
n=0.0130*0.220=0.00286=2.86*10⁻³ mol
Iayork
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Sep 16, 2018
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