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The work of a student to solve the equation 2(6y − 3) = 20 + 6y is shown below:

Step 1: 2(6y − 3) = 20 + 6y
Step 2: 8y − 5 = 20 + 6y
Step 3: 2y − 5 = 20
Step 4: 2y = 25
Step 5: y = 12.5

In which step did the student first make an error and what is the correct step?

Step 2: 8y − 5 = 10 + 3y
Step 2: 12y − 6 = 20 + 6y
Step 3: 6y − 3 = 2(18 + 3y)
Step 3: 2(6y − 3) = 18 + 3y

User Suriyanto
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1 Answer

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Step 2: 8y-5=10+3y is wrong
And the second step is right
User Waleed Mahmood
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