Question

Find the length of the base if the area of the trapezoid is 198 M2.

Answer 1

b2 is equal to 18 m



The area of a trapezoid is given by:

`A = 1/2 * (b_(1) + b_(2)) * h`

where b1 and b2 are the bases of the trapezois and h is the height. In this case we have that A = 198 b * 1 = 15 and h = 12 plugging this values into the equation above and solving for b2 we have:

`198 = 1/2 * (b_(2) + 15) * 122 * 198 = 12(b_(2) + 15)396 = 12(b_(2) + 15)396/12 = b_(2) + 1533 = b_(2) + 15b_(2) = 33 - 15b_(2) = 18`

Therefore b2 is equal to 18 m

Answer 2

The area of a trapezoid is given by:

`A=(1)/(2)(b_1+b_2)h`

where b1 and b2 are the bases of the trapezois and h is the height. In this case we have that A=198, b1=15 and h=12, plugging this values into the equation above and solving for b2 we have:

`\begin{gathered} 198=(1)/(2)(b_2+15)12 \\ 2\cdot198=12(b_2+15) \\ 396=12(b_2+15) \\ (396)/(12)=b_2+15 \\ 33=b_2+15 \\ b_2=33-15 \\ b_2=18 \end{gathered}`

Therefore b2 is equal to 18 m