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Find the length of the base if the area of the trapezoid is 198 M2.

Find the length of the base if the area of the trapezoid is 198 M2.-example-1
User AndyS
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2 Answers

18 votes
18 votes

b2 is equal to 18 m



The area of a trapezoid is given by:


A = 1/2 * (b_(1) + b_(2)) * h

where b1 and b2 are the bases of the trapezois and h is the height. In this case we have that A = 198 b * 1 = 15 and h = 12 plugging this values into the equation above and solving for b2 we have:


198 = 1/2 * (b_(2) + 15) * 122 * 198 = 12(b_(2) + 15)396 = 12(b_(2) + 15)396/12 = b_(2) + 1533 = b_(2) + 15b_(2) = 33 - 15b_(2) = 18

Therefore b2 is equal to 18 m

User McLovin
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3.1k points
26 votes
26 votes

The area of a trapezoid is given by:


A=(1)/(2)(b_1+b_2)h

where b1 and b2 are the bases of the trapezois and h is the height. In this case we have that A=198, b1=15 and h=12, plugging this values into the equation above and solving for b2 we have:


\begin{gathered} 198=(1)/(2)(b_2+15)12 \\ 2\cdot198=12(b_2+15) \\ 396=12(b_2+15) \\ (396)/(12)=b_2+15 \\ 33=b_2+15 \\ b_2=33-15 \\ b_2=18 \end{gathered}

Therefore b2 is equal to 18 m

User David Watson
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3.3k points