Question

WHAT IS THE LENGTH OF EF IN THE RIGHT TRIANGLE BELOW? answers are in the picture !

Answer 1

`Using\ the\ Pythagoreans'\ theorem,\ \\ \\ \\ c^2=a^2+b^2 \\ \\ 25^2=7^2+b^2 \\ \\ b^2=625-49 \\ \\ b= √(576) \\ \\ = 24\ units`

Answer 2

The length of EF in the given right triangle is:

Option: B 24

Explanation:

We are given a right triangle EFD with base DF=a=7 units.

Height EF=b

and Hypotenuse of the triangle ED=c=25 UNITS.

We know that in a right angled triangle we can apply Pythagorean Theorem.

According to Pythagorean Theorem we have:

`c^2=a^2+b^2\\\\(25)^2=(7)^2+b^2\\\\625=49+b^2\\\\b^2=625-49\\\\b^2=576\\\\b^2=(24)^2`

on taking square root on both side we get:

`b=\pm 24`

But as side of a triangle can't be negative.

Hence, b= 24 units.