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6 votes
Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.Function g is a transformation of the parent sine function, /(E)= sin(e)g(=) = join(2= - 5) + 1

Type the correct answer in the box. Use numerals instead of words. If necessary, use-example-1
User Pongpat
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2 Answers

18 votes
18 votes

The phase shift of function g(x) is 5/2, which indicates that the graph of this sine function is shifted 2.5 units to the right.

Step-by-step explanation:

The phase shift of function
g(x) = (1)/(9) \sin(2x - 5) + 1 can be found by analyzing the argument of the sine function. The general form for a sine function with a phase shift is f(x) = sin(bx - c), where c/b is the phase shift. Looking at the given function, we have a multiplier of 2 before the x and a subtraction of 5. Thus the phase shift is 5/2, because we divide the subtracted number by the multiplier of x.

In this specific case, the phase shift is positive, meaning the graph of the sine function has shifted to the right. A positive phase shift always indicates a shift to the right and vice versa for a negative phase shift.

User Igor Kroitor
by
3.4k points
24 votes
24 votes

GIVEN;

We are given a trig function as shown below;


g(x)=(1)/(3)sin(2x-5)+1

Required;

To determine the phase shift of this trig function.

Step-by-step solution;

For the function;


\begin{gathered} f(x)=A\cdot g(Bx-C)+D \\ \\ Where\text{ }g(x)\text{ }is\text{ }one\text{ }of\text{ }the\text{ }basic\text{ }trig\text{ }functions; \\ \\ (C)/(B)\text{ }is\text{ }phase\text{ }shift \\ \\ D\text{ }is\text{ }vertical\text{ }shift \end{gathered}

Therefore,


\begin{gathered} g(Bx-C)=sin(2x-5) \\ \\ B=2,C=5,D=1 \end{gathered}

Hence, phase shift is;


Phase\text{ }shift=(C)/(B)=(5)/(2)

ANSWER:


(5)/(2)

User Jeff Brown
by
2.2k points
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