Question

In a word game, you choose a tile from a bag, replace it, and then choose another. If there are 28 vowels and 12 consonants, what is the probability you will choose a consonant and then a vowel?

Answer 1

.21

Explanation:

Answer 2

Answer: 0.21

Explanation:

Given: The number of vowels in the bag = 28

The number of consonants= 12

The total number of letters in the bag =
`28+12=40`

Probability of choosing consonant :-

`P(C)=(12)/(40)=(3)/(10)`

After replacement the total number of letters remains same.

Probability of choosing vowel :-

`P(V)=(28)/(40)=(7)/(10)`

Now, the probability you will choose a consonant and then a vowel (independent events) is given by :-

`P(C)* P(V)=(3)/(10)*(7)/(10)=(21)/(100)=0.21`