Question

How many moles of AgNO3 are present in 1.50 L of a 0.050 M solution?

Answer 1

Answer: 0.075 Moles of AgNO3.

Step-by-step explanation:

Answer 2

To calculate the moles of AgNO3 in a solution, we need to know the volume and concentration of the solution.
Moles of AgNO3 = Volume of AgNO3 solution (L) * concentration of AgNO3 solution (M or mole/L) = 1.50 L * 0.050 M = 0.075 mole.

So 0.075 moles of AgNO3 are present in 1.50 L of a 0.050 M solution.