Question

if H(x)= 4x^2-16 was shifted 7 units to the right and 3 down, what would the new equation be? a. h(x)= 4(x+9)^2-17 b. h(x)= 4(x-9)^2-17 c. h(x)= 4(x-7)^2- 19 d. h(x)= 4(x+7)^2 +19

Answer 1

In general,
right shift h is given by
f(x-h)->g(x)
up shift is given by
f(x)+k->g(x)

So for h=7, and k=-3, we have
H(x-7)-3
=4(x-7)²-16-3
=4(x-7)²-19