Question

What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (−3, 1)?

y – 1=(x + 3)
y – 1=(x + 3)
y – 1= (x + 3)
y – 1= (x + 3)

Answer 1

y - 1 = 3/2(x + 3) last one

Explanation:

Answer 2

(2,2)(-2,-4)
slope = (-4 - 2) / (-2 -2) = -6/-4 = 3/2. the slope of this line is 3/2. A parallel line will have the same slope

y - y1 = m(x - x1)
slope(m) = 3/2
(-3,1)...x1 = -3 and y1 = 1
now we sub
y - 1 = 3/2(x - (-3)....not done yet
y - 1 = 3/2(x + 3) <=== its the last one