Question

Write the equation in standard form. Then factor the left side of the equation. 3x2 + 19x = 14

Answer 1

3x^2+19x-14=0 Standard form
(3x-2)(x+7)=0 Factored

Answer 2

Standard form of the equation,
`3x^2+19x-14=0`

Factor of the equation is,
`(x+7)(3x-2)=0`

Explanation:

The standard form of the quadratic equation is given as

`Ax^2+Bx+C = 0`

Given the equation:

`3x^2+19x = 14`

Subtract 14 from both sides we have;

`3x^2+19x-14=0`

⇒The standard form of the equation is,
`3x^2+19x-14=0`

Now, find the factor of the given equation:

`3x^2+19x-14=0`

⇒
`3x^2+21x-2x-14=0`

⇒
`3x(x+7)-2(x+7) = 0`

⇒
`(x+7)(3x-2)=0`

Therefore, the factor of the equation is,
`(x+7)(3x-2)=0`