Question

In geometric sequence the 4th term is 54 the 7th term is 1458 what is the 12th term

Answer 1

Let the common ratio be r.
a4=54
a7=1458
r^3=1458/54=27
r=27^(1/3)=3
therefore
a12=a7*r(12-7)=a7*3^5
=354294