Potassium fluoride (KF), a salt, has a gram-formula weight of 58.10 grams. How many grams would be needed to mix 1.00 liter of 5.00 molar salt solution? g

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asked Sep 1, 2018 115k views

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Stobbej · Answer 1 · 2018-09-08T03:03:40+0000

If one mole of KF is equal to 58.10 grams (gram-formula weight) then 5 moles should be 5 x 58.10 or 290.5 grams in 1 litre of water. This is taking the molar unit to be the 58.10 grams figure and then just multiplying it by 5 to get the conentration in the 1 liter of water.

Potassium fluoride (KF), a salt, has a gram-formula weight of 58.10 grams. How many grams would be needed to mix 1.00 liter of 5.00 molar salt solution? g

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