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Potassium fluoride (KF), a salt, has a gram-formula weight of 58.10 grams. How many grams would be needed to mix 1.00 liter of 5.00 molar salt solution? g
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Potassium fluoride (KF), a salt, has a gram-formula weight of 58.10 grams. How many grams would be needed to mix 1.00 liter of 5.00 molar salt solution? g

User Kamyarmg
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3 votes

Answer:

5.8

Step-by-step explanation:

Got it correct on Oddesyware ;)

User Jayqui
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If one mole of KF is equal to 58.10 grams (gram-formula weight) then 5 moles should be 5 x 58.10 or 290.5 grams in 1 litre of water. This is taking the molar unit to be the 58.10 grams figure and then just multiplying it by 5 to get the conentration in the 1 liter of water.
User Stobbej
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