Register
Potassium fluoride (KF), a salt, has a gram-formula weight of 58.10 grams. How many grams would be needed to mix 1.00 liter of 5.00 molar salt solution? g
115k views
5 votes
Potassium fluoride (KF), a salt, has a gram-formula weight of 58.10 grams. How many grams would be needed to mix 1.00 liter of 5.00 molar salt solution? g

User Kamyarmg
by
8.4k points

2 Answers

3 votes

Answer:

5.8

Step-by-step explanation:

Got it correct on Oddesyware ;)

User Jayqui
by
8.7k points
7 votes
If one mole of KF is equal to 58.10 grams (gram-formula weight) then 5 moles should be 5 x 58.10 or 290.5 grams in 1 litre of water. This is taking the molar unit to be the 58.10 grams figure and then just multiplying it by 5 to get the conentration in the 1 liter of water.
User Stobbej
by
7.8k points
← Prev Question Next Question →

Related questions

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

Other Questions

Compare and contrast an electric generator and a battery??
How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
As an object’s temperature increases, the ____________________ at which it radiates energy increases.
Why is gold preferred as a superior metal over silver and bronze?
What is the evidence of a chemical reaction when the fireworks go off
Link Copied!