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Logarithms 8^(x-9) = 19^(3x+2)
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Logarithms
8^(x-9) = 19^(3x+2)

User Dean Elbaz
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\bf 8^(x-9)=19^(3x+2)\implies log(8^(x-9))=log(19^(3x+2)) \\\\\\ (x-9)log(8)=(3x+2)log(19)\impliedby distributing \\\\\\ xlog(8)-9log(8)=3xlog(19)+2log(19) \\\\\\ xlog(8)-3xlog(19)=9log(8)+2log(19)\impliedby \textit{common factor} \\\\\\ x[log(8)-3log(19)]=9log(8)+2log(19) \\\\\\ x=\cfrac{9log(8)+2log(19)}{log(8)-3log(19)}
User Shachar
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