menu
Qammunity.org
Login
Register
My account
Edit my Profile
Private messages
My favorites
I need to graph a parabola. I need to find the vertex and a couple coordinates. y=-x^2+2x-4
Ask a Question
Questions
Unanswered
Tags
Ask a Question
I need to graph a parabola. I need to find the vertex and a couple coordinates. y=-x^2+2x-4
asked
Jan 6, 2018
150k
views
1
vote
I need to graph a parabola. I need to find the vertex and a couple coordinates.
y=-x^2+2x-4
Mathematics
college
Rahnzo
asked
by
Rahnzo
8.2k
points
answer
comment
share this
share
0 Comments
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
1
Answer
4
votes
hello :
y=-x²+2x-4
y = -(x²-2x)-4
y = - (x²-2x+1)+1-4
y = - (x-1)² -3
the vertex is : (1 , -3 )
Reza Ameri
answered
Jan 11, 2018
by
Reza Ameri
8.1k
points
ask related question
comment
share this
0 Comments
Please
log in
or
register
to add a comment.
← Prev Question
Next Question →
No related questions found
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.
9.4m
questions
12.2m
answers
Categories
All categories
Mathematics
(3.7m)
History
(955k)
English
(903k)
Biology
(716k)
Chemistry
(440k)
Physics
(405k)
Social Studies
(564k)
Advanced Placement
(27.5k)
SAT
(19.1k)
Geography
(146k)
Health
(283k)
Arts
(107k)
Business
(468k)
Computers & Tech
(195k)
French
(33.9k)
German
(4.9k)
Spanish
(174k)
Medicine
(125k)
Law
(53.4k)
Engineering
(74.2k)
Other Questions
How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Twitter
WhatsApp
Facebook
Reddit
LinkedIn
Email
Link Copied!
Copy
Search Qammunity.org