Question

What is the sum of a 6-term geometric series if the first term is 23 and the last term is 1,358,127?

Answer 1

Last term is 1,527,890.

Explanation:

Answer 2

The sum of 6-term of geometric series is 1,527,890

Explanation:

First term:
`a=23`

Last term:
`a_6=1358127`

Formula:

`a_n=ar^(n-1)`

`S_n=(a(r^n-1))/(r-1)`

Put n=6 into formula

`a_6=23r^5`

`1358127=23r^5`

`r^5=59049=9^5`

`r=9`

Common Ratio: r=9, a=23 and n=6

`S_6=(23(9^6-1))/(9-1)`

`S_6=1527890`

Hence, The sum of 6-term of geometric series is 1,527,890