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What is the sum of a 6-term geometric series if the first term is 23 and the last term is 1,358,127?

User TchiYuan
by
8.2k points

2 Answers

1 vote

Answer:

Last term is 1,527,890.

Explanation:

User Bendemann
by
7.9k points
6 votes

Answer:

The sum of 6-term of geometric series is 1,527,890

Explanation:

First term:
a=23

Last term:
a_6=1358127

Formula:


a_n=ar^(n-1)


S_n=(a(r^n-1))/(r-1)

Put n=6 into formula


a_6=23r^5


1358127=23r^5


r^5=59049=9^5


r=9

Common Ratio: r=9, a=23 and n=6


S_6=(23(9^6-1))/(9-1)


S_6=1527890

Hence, The sum of 6-term of geometric series is 1,527,890

User PruitIgoe
by
7.7k points
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