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What is the oblique asymptote of the function f(x) = the quantity of x squared plus 6 x plus 10, all over x plus 2 ? (1 point)?

User PureGero
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2 Answers

4 votes
You can rewrite the equation as:


x+4 + \frac2{x+2}

For extremely high (or low) x, the 2/(x+2) term goes to 0, so what remains then is:

f(x) = x+4.

This is the function that describes the asymptote.


User AllramEst
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8.5k points
4 votes

Answer:

oblique asymptote at y=x+4

Explanation:

To find out oblique asymptote we use long division

x + 4

--------------------------------

x+2 x^2+6x+10

x^2 + 2x

----------------------------------(subtract)

4x + 10

4x + 8

----------------------------------------(subtract)

2

oblique asymptote at y=x+4

User Alexander Ruliov
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8.1k points