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How many x intercepts appear on the graph of this polynomial function? f(x)=x^4-5x^2

User Gabor
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2 Answers

4 votes
The function can be factorised to give x²(x²-5). Therefore the graph will touch the x axis at zero and cut it at -√5 and √5, giving three x-intercepts. To check, let's look at a graph my calculator drew of this function:

How many x intercepts appear on the graph of this polynomial function? f(x)=x^4-5x-example-1
User Jeggy
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7.6k points
1 vote

From the diagram you can see that the graph of function has three x-intercepts. If you need the coordinates of these points, then you should substitute y=0 and solve the received equation:


0=x^4-5x^2.

First, factor this expression:


x^2(x^2-5)=0,\\x^2(x-√(5)) (x+√(5))=0.

This means that


x_1=0, x_2=√(5) ,x_3=-√(5).

The x-intercepts are points


(0,0), (√(5),0), (-√(5),0).

Answer: 3 x-intercepts.

How many x intercepts appear on the graph of this polynomial function? f(x)=x^4-5x-example-1
User Nlassaux
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7.3k points