Answer: Second option is correct.
Explanation:
Since we have given that
In Δ TSR,
TR= 3
SR= 4
∠STR = 66°
So, we will first congruent the two triangle i.e.
Consider ΔPTQ and ΔTSR,
PT= TR = 3 (∵ Radii of circle )
∠PTQ= ∠STR = 66° (∵ Vertically opposite angles are equal )
TS= QT = 3 ( ∵ Radii of circle )
∴ ΔPTQ ≅ ΔTSR ( By SAS congruence )
So, by CPCT( corresponding parts of congruent triangle ),
PQ= SR = 4
Hence, PQ =4
Therefore, Second option is correct.