we know that
m∠SQR+x=
-------> by supplementary angles
so
m∠SQR=

The sum of the internal angles of a triangle is equal to
degrees
m∠SQR+m∠QSR+m∠SRQ=

substitute the values in the formula
m∠SQR+
+
=

m∠SQR=
degrees
Find the value of x
m∠SQR=

x=
-m∠SQR
x=

x=
degrees
therefore
the answer is
the value of x is
degrees