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What are the x-intercepts of the function f(x) = –2x2 – 3x + 20?

2 Answers

3 votes

The root sof this quadratic equation are -4 and 2.5.


The roots of any quadratic can be found by using the quadratic equation. The equation is below for you.



\frac{-b +/- \sqrt{b^(2)- 4ac}}{2a}


In this equation you use the number attached to x^2 as the a, which in this case is -2. The number attached to x as b, which is in this case -3. And the number at the end as c, which is 20. From there you solve for the answers.



\frac{3 +/- \sqrt{-3^(2)- 4(-2)(20)}}{2(-2)}


(3 +/- √(9 + 160))/(-4)


\frac{3 +/- 13}}{4}


Now you separate and get the two separate answers. First the positive.



\frac{3 + 13}}{4}


\frac{16}}{4}

4


Now the negative



\frac{3 - 13}}{4}


\frac{-10}}{4}

-2.5

User Maxschlepzig
by
8.6k points
6 votes

Answer:

Its A

Explanation:

I just took the test

OWO

User Guish
by
7.9k points

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