Register
A bullet of mass m= 10 gram strikes a ballistic pendulum of mass m=2.0 kg. the center of mass of the pendulum rises a vertical distance of h=12 cm. assuming the bullet remains embedded in the pendulum,
78.1k views
3 votes
A bullet of mass m= 10 gram strikes a ballistic pendulum of mass m=2.0 kg. the center of mass of the pendulum rises a vertical distance of h=12 cm. assuming the bullet remains embedded in the pendulum, calculate its initial speed.

User Srdjan Dejanovic
by
8.5k points

1 Answer

4 votes
Assumption made: No energy is loss!
The g is 10N/kg
Total mass = 0.01kg+2kg= 2.01kg
Gravitational Potential Energy= 2.01kg * 0.12m * 10N/kg = 2.412J
Kinetic energy = 2.412J since no energy is lost
Velocity =( (2.412J * 2 )/ 2.01kg )^0.5= 1.55m/s
User Guitz
by
8.3k points
← Prev Question Next Question →

Related questions

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

Other Questions

Physical properties of minerals graphic organizer
A snowball is launched horizontally from the top of a building at v = 16.9 m/s. If it lands d = 44 meters from the bottom, how high (in m) was the building?
What type of rock is the Haystack rock (igneous, Metamorphic, or Sedimentary)
what is a device that transforms thermal energy to mechanical energy
How many light sources do you know Pls list them
Link Copied!