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In the below system, solve for y in the first equation. x + 3y = 6 2x − y = 10 1/3x + 2 -1/3x + 6 −x + 2 -1/3x + 2

In the below system, solve for y in the first equation. x + 3y = 6 2x − y = 10 1/3x + 2 -1/3x + 6 −x + 2 -1/3x + 2
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In the below system, solve for y in the first equation.

x + 3y = 6
2x − y = 10

1/3x + 2
-1/3x + 6
−x + 2
-1/3x + 2

User Dh YB
by
7.8k points

1 Answer

3 votes
If you want me to just solve the first one then the answer could be 1 and then if x was 2 then it would end up with the sum of 6.
User Usha
by
9.2k points
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