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What are the center and radius of a circle defined by the equation x^2+y^2- 6x+ 8y+ 21=0? A. Center (3,-4); radius 4 B. Center (3,-4); radius 2 C. Center (-3,4); radius 2 D. Center (-3,4); radius 4 PLEASE
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Feb 1, 2018
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What are the center and radius of a circle defined by the equation x^2+y^2- 6x+ 8y+ 21=0?
A. Center (3,-4); radius 4
B. Center (3,-4); radius 2
C. Center (-3,4); radius 2
D. Center (-3,4); radius 4
PLEASE HELP ME QUICK!
Mathematics
high-school
Nick Davies
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Nick Davies
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Answer:
It is B, Thank me later
Step-by-step explanation:
Jannina
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Feb 4, 2018
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Jannina
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You have to complete the square. When you do this you get an equation that looks like this: (x-3)^2 + (y+4)^2 = 4. So your center is (3, -4) and your radius is 2. That looks like B to me!!!
Lefloh
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Feb 8, 2018
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Lefloh
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