Question

in the reaction mgcl2+2koh mg(oh)2 +2kci IF 1 MOLE MGCL2 IS added to 3 moles koh what is the limiting reagent

Answer 1

For 1 mole of MgCl2, it would require 2 moles of KOH. ( 1 : 2 mole ratio)

Since you have 3 moles of KOH, it is in excess, and MgCl2 is the limiting reactant.

Answer 2

Answer:
`MgCl_2`

Explanation:

`MgCl_2+2KOH\rightarrow Mg(OH)_2+2KCl`

According to stoichiometry,

1 mole of
`MgCl_2` reacts with 2 moles of
`KOH`

Thus when 1 mole of
`MgCl_2` is added to 3 moles of
`KOH` , (3-2)moles= 1 mole of
`KOH` will remain unused.

Thus
`MgCl_2` is the limiting reagent as it decides the formation of products.

`KOH` is excess reagent as it remains unused.