Question

Which equation is set up correctly to determine the volume of a 1.5 mole sample of oxygen gas at 22°C and 100 kPa?

Answer 1

Hello!

Which equation is set up correctly to determine the volume of a 1.5 mole sample of oxygen gas at 22°C and 100 kPa?

We have the following data:

v (volume) = ? (in L)

n (number of mols) = 1,5 mol

T (temperature) = 22 ºC

First let's convert the temperature on the Kelvin scale, let's see:

TK = TºC + 273,15

TK = 22 + 273,15

TK = 295,15

P (pressure) = 100 kPa → P = 100000 Pa → P ≈ 0,987 atm

R (gas constant) = 0,082 atm.L / mol.K

We apply the data above to the Clapeyron equation (gas equation), let's see:

`P*V = n*R*T`

`0,987*V = 1,5*0,082*295,15`

`0,987\:V = 36,30345`

`V = (36,30345)/(0,987)`

`\boxed{\boxed{V \approx 36,78\:L}} \end{array}}\qquad\checkmark`

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I Hope this helps, greetings ... Dexteright02! =)