Question

Solve the system of equations
-2x+5y=13
16x+3y=25

Answer 1

-2x+5y=13
-5 -5
=8
-2(negative two)
-2 /8 =???
That's how to find answer

Answer 2

-2x + 5y = 13
16x + 3y = 25

To solve this you have to cancel the x first so you multiply the first equation by 8

-2x + 5y = 13. All of that times 8
-16x + 40y = 104


Now that you have this you can cancel x

-16x + 40y = 104
16x. +. 3y. = 25

X cancel

40y = 104
3y. = 25

You add the y and the numbers

43y = 129
/43. /43

Y = 3


Now you plug y in one of the equations

16x + 3y = 25
16x.+ 3(3) = 25
16x + 9 = 25
-9. -9

16x = 16
/16. /16

X = 1



Y = 3 and X = 1