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What is the approximate solution of e2x−3 = 7?
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What is the approximate solution of e2x−3 = 7?

User Wonko
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2 Answers

1 vote

The approximate solution is .69314718

User Shubham Kadlag
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4 votes
e2x-3=7 (multiply by ln e on both sides)
ln e of e=1
>>> 2x-3=ln 7
x=(ln 7 + 3)/2
x=2.47 (to 3 s.f)
User Bhupesh Varshney
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6.2k points
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