a point , (x,y) is reflected across the y axis. the resulting point is (-x,y)
so
if (5.75,0) is the reflected point, then (-5.75,0) is the original
the distance is the double the absolute value of the x value (basically a horizontal line beteen the 2 points)
so
2|-5.75|=2(5.75)=11.5
distance is 11.5 units