How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution. A. 11 L B. 15 L C. 25 L

asked Jun 22, 2018 173k views

5 votes

How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution.

A. 11 L

B. 15 L

C. 25 L

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4 votes

Answer:

Explanation:

The answer is B hope this helps!

Ymajoros answered Jun 23, 2018

6.4k points

3 votes

The answer is B

15 L of pure water must be mixed with 10 L of a 25% acid solution to reduce it to a 10% acid solution

Donelle answered Jun 28, 2018

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