Question

A certain board game requires the roll of 3 standard dice to determine the outcome of a battle. what is the probability that at least one of the dice will show an even number?

Answer 1

Answer: 7/8

I took a lucky guess on my quiz and got it right answer, thought everyone would like to know.

Answer 2

`(7)/(8)`

Explanation:

We are given that three dice rolled.

Even number in a dice =3

Odd numbers in a dice =3

Total number of cases in a dice=6

Probability =
`(number\;of\;favorable\;cases)/(total\;number\;of\;cases)`

Probability of getting an odd number when a dice rolled =
`(3)/(6)=(1)/(2)`

Probability that three dice show odd number when three dice rolled=
`((1)/(2))^3=(1)/(8)`

Therefore, the probability that at-least one of the dice will show an even number=
`1-(1)/(8)=(7)/(8)`

Answer:
`(7)/(8)`