Question

Which would react chemically by forming an ionic bond?

A. 2 chlorine atoms with 7 valence electrons each
B. 1 neon atom with 8 valence electrons and 1 lithium atom with 1 valence electron
C. 1 sodium atom with 1 valence electron and 1 chlorine atom with 7 valence electrons
D. 2 hydrogen atoms with 1 valence electron each and 1 oxygen atom with 6 valence electrons

Answer 1

C. Na would form a 1+ ion losing its electron to the Cl to make a Cl- ion. Gives the molecule NaCl

Answer 2

c. One sodium atom with 1 valence electron and 1 chlorine atom with 7 valence electrons

Step-by-step explanation:

The electronic configuration of one sodium atom is

Na = 2, 8, 1

The electronic configuration of one chlorine atom is

Cl = 2, 8, 7

Therefore Na atom has 1 electron in its valence shell whereas Cl atom has 7 electron in its valence shell.

So Na atom combines with Cl atom to form NaCl atom by transferring atom from the Na atom to Cl atom forming
`Na^(+)` ion and
`Cl^(-)` ion

Thus Na and Cl react to form ionic bond.