Question

The volume of a 48.03 g sample of methane gas is 31.7 L at 53 °C and 5.41 atm.What will its volume be at 91.7 °C and 1.9 atm?

Answer 1

To answer this question we have to use the combined law of gases:

`(P1V1)/(T1)=(P2V2)/(T2)`

Convert the temperatures to kelvin degrees:

`\begin{gathered} 53+273.15=326.15 \\ 91.7+273.15=364.85 \end{gathered}`

Solve the equation for V2 and replace for the given values:

`\begin{gathered} V2=(P1V1T2)/(T1P2) \\ V2=(5.41atm\cdot31.7L\cdot364.85K)/(326.15K\cdot1.9atm) \\ V2=100.97L \end{gathered}`

It means that the volume of the gas will be 101L.

The correct answer is c. 101.